View Single Post
 
Reply
Posted 2003-10-01, 11:05 AM in reply to Titusfied's post "Solve for Length "X""
The base if one triangle is X/(root(2)) Therefore, the length of the rectangle is 60(root(2)) - X(root(2)).

Since the height of the triangle is also X/(root(2)), the area of the rectangle is (root(2))(60-X)(X)/root(2) = 60X-X^2

The area of both triangles together is BH which is (X^2)/2

Therefore, the total area (given) 1250 = (X^2)/2 + 60X - X^2
= 60X - (X^2)/2

X = (apprx) 26.835
D3V said:
This message is hidden because D3V is on your ignore list.
What is it they say about silence being golden?
Old
Profile PM WWW Search
Medieval Bob enjoys the static noises of ten television sets simultaneously tuned to 412.84 MHzMedieval Bob enjoys the static noises of ten television sets simultaneously tuned to 412.84 MHz
 
 
Medieval Bob