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Solve for Length "X"
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Posted 2003-10-01, 11:05 AM in reply to
Titusfied
's post
"Solve for Length "X""
The base if one triangle is X/(root(2)) Therefore, the length of the rectangle is 60(root(2)) - X(root(2)).
Since the height of the triangle is also X/(root(2)), the area of the rectangle is (root(2))(60-X)(X)/root(2) = 60X-X^2
The area of both triangles together is BH which is (X^2)/2
Therefore, the total area (given) 1250 = (X^2)/2 + 60X - X^2
= 60X - (X^2)/2
X = (apprx) 26.835
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