A simple math problem

[Ganga]

I got stuck on this part, some one help please.

I need to solve for X:


Y=(X+17)/(x-15)


The answer should be like X= Y+something/ Y+something.

[Mantralord]

I think its X=(x+17+15y)/y

[Ganga]

Thanks for trying, but you have to put all x on 1 side. The question was to find the inverse of that funtion.

[kaos]

A simple math problem


Define SIMPLE!

[platnum]

x=y-17

[Sovereign]

Thats not simple math...thats retard math...

[Ganga]

Appearly you are worst than retard.

[!King_Amazon!]

I know it looks like a fucked up "S" on a graph.

[Sovereign]

Ummm no ganga. ITs because i dont feel like doing ur math homework for you you lazy bum.

[Ganga]

Appearly you don't even know how to read either. Reread my first post couple times, and if you still have problem understanding, you should really quite school.

and stop spamming.

[!King_Amazon!]

you should really quite school.

[Sovereign]

i reread it once, and i still dont see what your talking about...the retard math problem statement was aimed towards platnum because of his x=y-17...thats for retards, because its already answered.

[Ganga]

x=y-17 is wrong, "its already answered"???

[Sovereign]

NO NO NO . it hought he was giving an exdample of a simple math problem. you said solve for x, i thought his problem was x=y-17. I called it a retard problem becuase that was already solved for x.

[Ganga]

LOl, Ok then I think i got everything wrong then, my bad calling you. We really need some system that say, this post is refer to post # 1 or what ever.

[Sovereign]

iz all good :)

[!King_Amazon!]

It seems to me that x is always = to 15, which isn't possible since you can't divide by 0. Let me try this again.

[uncapped]

Uh, y = 2x?

I dunno, I'm in stupid people math.

[Ganga]

The answer should be something like this:


f(x) = Ay + B/Cy + D


and I have to find the values for A, B, C, D with A > 0.

That's the question.

I know C is 1 that's all I know for now.

[!King_Amazon!]

Y | X
-5 | 9.66666....
-2 | 4.33333....
0 | -17
-2 | 47
-5 | 23


If you can figure out what the function is, I'm proud of you.

This is too hard for my sophomoreness.

[Ganga]

Did you just put that function on the calulator and look at the table?

[!King_Amazon!]

No, I graphed the function then graphed y=-5 y=-2 y=0 etc. and found the intersections.

[Medieval Bob]

I can give you:

x = 32/(y-1) + 15

[platnum]

http://www.iownjoo.com/freeimghost/platnum/mathzel.GIF

i came up with that, only way i could get x on one side.

[Chruser]

x = (15y + 17)/(y - 1)

[Sovereign]

Chruser anyway you can show your work in steps...im actually intrerested in how you did tha

[Chruser]

y = (x + 17) / (x - 15)
y(x-15) = x + 17
xy - 15y = x + 17
xy - x = 15y + 17
x(y - 1) = 15y + 17
x = (15y + 17) / (y -1)

[Chruser]

Oh, if you need to check your solution, you can always try this out:

http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=mathcom&s1=equations&s2=solve&s3=basic

Works really well up to exact fourth-grade solutions. If you want to see how good it really is, try solving this equation for x:

7a^4+17x^4+7x^3+17x^2+7x+7a^3=7

It might take a while, but the results are impressive.

Of course, if you have a lot of homework on a really tough equation to deal with, you can always use this web-based equation solver and check everything step-by-step to see if you're still on-track. If you suddenly get a bunch of strange square and cube roots all over the place, you might, for instance, have messed with the denominator a bit too much, so go back a step and try something else.

[platnum]

heh, i allmost had it right

[Ganga]

Ah, Chruser, only if you done that 2 days earlier I would goten a 100% on my homework... :( stupid web assignments. Thanks anyway! Nice website you have there thanks for that too.

[slaynish]

whoa thanks.. ill be needing this next year and some of this year...

[Chruser]

Feel free to shout again if you need more help, and I just might be able to find out what I'm doing.

[!King_Amazon!]

http://www.iownjoo.com/freeimghost/platnum/mathzel.GIF

i came up with that, only way i could get x on one side.

Well from that you can solve for Y, then solve for X, since X/X=1.

[Medieval Bob]

Well that is true up until xy - 15y - 17 = x

From there you need to subtract x from both sides and add 15y and 17 to both sides.

That gives you xy - x = 15y + 17
Then factor out the x which gives you x(y - 1) = 15y + 17
Then divide both sides by (y - 1)


x = (15y + 17)/(y - 1)

[!King_Amazon!]

Why can't we just solve for X? It's a lot easier.

-14y-17=1
-14y=18
y=-1.29

xy-15y=x+17
-1.29x-(15 X -1.29)=x+17
X=1.03

Damn you smart people.

[RoboticSilence]

I used MATHS and solved it easily.

[Medieval Bob]

Well you can't solve for y because when you divided by x on both sides, you fucked up. You would have also had to divide 15y and 17 by x also.

To keep both sides of the equation equal, you have to divide both sides by the same thing. You can't divide different terms by something, it must be the whole.