The Next Math Riddle

[Grav]

Two people are both at Point A. Person 1 walks North at a rate of 783 km/hr. Person 2 walks in any direction at a different speed. Where will they meet?

[Senesia]

Person 1 walks really fast.

They will meet at Point A, if they don't change direction during their walks.

Or the exact opposite of Point A (The other side on Earth, or whatever Sphere they are on.)

[Premier24]

Ride each other

[Senesia]

Forgot to mention...if Person 2 walks North or South, then they could meet anywhere along the North-South route.

[TheStryker]

No matter what direction person 2 runs, they will meet at point A

[Senesia]

Point A is one of the possible locations, yes.

But there is more than one possible "point" where they could meet.

[Kuja`s #1]

:confused:

[TheStryker]

Otherside of the earth? like you said above, that makes sense too

[J_iceman]

Then the answer would have to be in variables example 3x + y where x and y would be there starting points (why do you guys like to confuse people??) just for the fun of it huh?? O_o

[Grav]

So far none of you have the right answer.

Spoke too soon

[WetWired]

The answer is that they wouldn't. At that speed, the first person would fling themself free of Earth's gravity and speed off into deep space. Even if the second person moved in the same direction at a greater speed, they wouldn't meet as their arcs would be different because of the difference in speed.

[Medieval Bob]

omfg WW said "fucking pwnt"

[D3V]

They will meet at point B, because whenever they meet it can't be considered point A, because if that were true you can't have a starting point and a finishing point be the same thing, it will have to be point A and point B.

[Senesia]

They will meet at point B, because whenever they meet it can't be considered point A, because if that were true you can't have a starting point and a finishing point be the same thing, it will have to be point A and point B.

Read WW's post...

Blah, 783 km/hr.

[Grav]

The other answer is that it's impossible to walk at 783km/hr

[Senesia]

Because it is two times Light speed and more?


I read that as m/s, and I meant Sound Speed...

[RoboticSilence]

No, because it's running.

[Mantralord]

783 km/hr isnt anything special...supersonic jets usually travel at 2 or 3 times that...

[Chruser]

I thought walking was defined by constantly having contact with the ground with at least one foot, not by actual speed? Besides, the speed of light is over 1 billion km/h (1,079,252,849), 670,616,630 mph, or mach 904,019.

[!King_Amazon!]

If he is walking at that speed, he wouldn't detach from earths gravity, because the definition of walking is having at least 1 foot on the ground at once. If you are floating in space, you are no longer walking.

I like the "you can't walk at that speed" answer best.

[Grav]

I've had dicks implanted in me many times by surgeons.

[!King_Amazon!]

Did you mean to put this in the medical problems thread?

[Grav]

Well, WetWired (http://www.aim.americangreetings.com/display.pd?path=24116&bfrom=1&prodnum=3040924&) is just a fucking genius thats all.

[D3V]

As Dr. Evil would say.... "Riiiiiiight"

my answer is correct, he didn't mention the variables being a factor in this problem, therefore they would meet at POINT B!

[slaynish]

scott, throw me a frickin bone here

[Senesia]

my answer is correct, he didn't mention the variables being a factor in this problem, therefore they would meet at POINT B!

No.

[Titusfied]

This riddle sucks. Mine is better, and it actually has a logical answer...

[Randuin]

Chruser... Isn't speed of light 3x10^8 m/s anyway.
They would meet at the end point of Vector C. Done

[Titusfied]

Actually its 2.9999....X 10^8, but mostly everyone just rounds up... ;)

[Randuin]

Lol... But when you use exponent 3 you're talking km/s right?

[Titusfied]

Doh, typo, edited...

[Randuin]

Heh... I was wondering what kind of fucked up ultra magenta slow-ass light you were getting :P