C programming Count uppercase letters in a sentence

I don't know where to start or how to write the program I need some help I am trying to program an uppercase character is an character whose ASCII value is between 65(A) and 90(Z). I need to write a program that prompts the user to enter a string from the keyboard and will count the number uppercase character and replace each uppercase character by the corresponding lowercase character.

I don't know where to start or how to write the program I need some help I am trying to program an uppercase character is an character whose ASCII value is between 65(A) and 90(Z). I need to write a program that prompts the user to enter a string from the keyboard and will count the number uppercase character and replace each uppercase character by the corresponding lowercase character.

PHP Code:

#include <stdio.h>

int main(void)
{
     char string[50];
     gets(string);
     int count = 0;
     int i;
     for(i = 0; string[i]; i++)
     {
          if(string[i] >= 'A' && string[i] <= 'Z')     
          {
               count++;
          }
     }

     printf("%d", count);
} 


Actually, it would be
for(i=0;i<strlen(string);i++)
not
for(i=0;i<string[i];i++)

Actually, it would be for(i=0;i<strlen(string);i++) not for(i=0;i<string[i];i++)

Actually, I don't even know why I did

i<string[i]

I meant to just say

string[i]

I'll go ahead and change that.

But yea, WW's method is better. Use strlen.