Well, I'm going to go ahead and post the answer:

If you have the general equation: x = (a + b) cos(t) - b cos((a/b + 1)t), y = (a + b) sin(t) - b sin((a/b + 1)t) then area = pi*b^2(m^2 + m).

There's actually a pretty creative way using calculus to do it if anyone's interested. That's the one I was shooting for. Plugging it into a formula is no fun.

I'll get another one up soon.