Anybody good with Calculus?
 

What is the Limit as H goes to 0 of

(1/H)*[ (1+H)^10 - 1 ]

Comment if you know the answer. Vote if you would like to guess. (I can find the answer, but I haven't yet because I don't feel like multiplying that out if there is another way to do it.)

It's zero, because (1+H) = 1
H is approaching zero.
1 ^ 10 = 1 because 1*1*1*1*1*1*1*1*1*1 = 1
1 -1 = 0
zero multiplied by anything is 0

Thus the answer is zero




I made a stupid mistake, read below to see my 2nd attempt at this problem

I think it's 10...

Well, at first glance i would think that it approches zero because of the reasons you gave. That is not true though. A somewhat good check to do is plug in some values for x that get smaller and smaller and see what number it looks like it's getting close to... I've forgotten how to get a for-sure answer. But the answer to your problem is 10.


But I soo stupidly voted 0 on my first guess, but, well... whatever

You completely forgot about the (1/H). You can't divide by zero my friend. Also, Wiccan, you're right. A little calculator work provides that it ends up coming to 10. Thanks for the help. May the Lord of Calculus shine upon your den, and may your feast be bountiful.

And may you get herpes. :)

oh dear lord, I hate calculus.

hey, i notice that u HAVE to have a calculator to do this problem, quite a trick problem here
The first half of the problem (1/h) comes out to be approaching infinity
the second half of the problem approaches zero.
at first glance, a really big number multiplied by zero is zero.
but then i noticed the 2nd part isn't zero, but it approaches zero. so it's actually a really big number multiplied by a really small number.
And it just so happens, the really big number is exactly 10 times bigger than the small number. thus the answer is 10. *smacks myself for answer earlier*

*smacks you also*