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Problem #3?
Box 1 contains 1000 bulbs of which 10% are defective. Box 2 contains 2000 bulbs of which 5% are defective. Two bulbs are picked from a randomly selected box.
(a) Find the probability that both bulbs are defective. (b) Assuming that both are defective, find the probability that they came from box 1. *Not the easiest problem, but very doable for y'all. |
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(b) 1/4? |
It matters not whether you win or lose; what matters is whether I win or lose.
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(a) Nope. Too large. How did you get the 7.5%? It's not correct by the way.
(b) Nope... |
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Well, if it was box 1, the first bulb has a 10% chance of being defective, but for a second consecutive bulb to be picked out of box 1, it is a 99/999 times that 1/10. Take that hint and go with it!
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It matters not whether you win or lose; what matters is whether I win or lose.
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Ok, let me take another stab at answer a. ~.5599%?
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A defective bulb from box one is probabilty 100/1000 --> 1/10
A defective bulb from box two is probability 100/2000 --> 1/20 a) 200/3000 --> 2/30 b) Oh God, I hate these questions. Gotta draw bloody diagrams. Gimme a few min. Ah fuck it. Can't be bothered. Go with: a) 2/30 b) 1/30 ??? |
No to all. It was actually a lot tougher a problem than I initially thought.
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Bleh...I dislike math...
Well, not really I just don't like it. |
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Chance of defective for second pick is 199/2999 = 6.6355% Chance of that happening is .4424%. Chance the first was from box one: 100/200 = 50%. Chance the second was from box one as well: 99/199 = 49.75% Chance of both being from box one is 24.87%. Unless you have to factor in the total number in each box... In which case... Fuck it. I get of in 5 minutes. |
ITS IN PLAIN SIGHT!!! they were both picked from the same box!! if they were picked from box 1 then...
A) 15 percent chance they are both defective! B) DUH 50% chance!!! |
Holy God I hate math. :P
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Doh on the wording.
I suppose "Two bulbs are picked from a randomly selected box." would imply that they were both picked from one box. That means b) is 50%. Now, however, the method of solving a chances. 50% chance of box 1 and percentage of 2 defective there is 100/1000 * 99/999 = .990990% (repeating) chance. 50% chance of box 2 and percentage of 2 defective there is 100/2000 * 99/1999 = .2476238% chance. Add half the first percent to half the second percent, and there's your answer. .6193% chance of having 2 defective bulbs. (That is, if you're assuming they're both picked from one box.) |
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