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A simple math problem
I got stuck on this part, some one help please.
I need to solve for X: Y=(X+17)/(x-15) The answer should be like X= Y+something/ Y+something. |
I think its X=(x+17+15y)/y
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Thanks for trying, but you have to put all x on 1 side. The question was to find the inverse of that funtion.
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Define SIMPLE! |
x=y-17
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Thats not simple math...thats retard math...
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Appearly you are worst than retard.
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I know it looks like a fucked up "S" on a graph.
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Ummm no ganga. ITs because i dont feel like doing ur math homework for you you lazy bum.
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Appearly you don't even know how to read either. Reread my first post couple times, and if you still have problem understanding, you should really quite school.
and stop spamming. |
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i reread it once, and i still dont see what your talking about...the retard math problem statement was aimed towards platnum because of his x=y-17...thats for retards, because its already answered.
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x=y-17 is wrong, "its already answered"???
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NO NO NO . it hought he was giving an exdample of a simple math problem. you said solve for x, i thought his problem was x=y-17. I called it a retard problem becuase that was already solved for x.
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LOl, Ok then I think i got everything wrong then, my bad calling you. We really need some system that say, this post is refer to post # 1 or what ever.
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iz all good :)
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It seems to me that x is always = to 15, which isn't possible since you can't divide by 0. Let me try this again.
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Uh, y = 2x?
I dunno, I'm in stupid people math. |
The answer should be something like this:
f(x) = Ay + B/Cy + D and I have to find the values for A, B, C, D with A > 0. That's the question. I know C is 1 that's all I know for now. |
Y | X
-5 | 9.66666.... -2 | 4.33333.... 0 | -17 -2 | 47 -5 | 23 If you can figure out what the function is, I'm proud of you. This is too hard for my sophomoreness. |
Did you just put that function on the calulator and look at the table?
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No, I graphed the function then graphed y=-5 y=-2 y=0 etc. and found the intersections.
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I can give you:
x = 32/(y-1) + 15 |
http://www.iownjoo.com/freeimghost/platnum/mathzel.GIF
i came up with that, only way i could get x on one side. |
x = (15y + 17)/(y - 1)
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Chruser anyway you can show your work in steps...im actually intrerested in how you did tha
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y = (x + 17) / (x - 15)
y(x-15) = x + 17 xy - 15y = x + 17 xy - x = 15y + 17 x(y - 1) = 15y + 17 x = (15y + 17) / (y -1) |
Oh, if you need to check your solution, you can always try this out:
http://www.hostsrv.com/webmab/app1/M...solve&s3=basic Works really well up to exact fourth-grade solutions. If you want to see how good it really is, try solving this equation for x: 7a^4+17x^4+7x^3+17x^2+7x+7a^3=7 It might take a while, but the results are impressive. Of course, if you have a lot of homework on a really tough equation to deal with, you can always use this web-based equation solver and check everything step-by-step to see if you're still on-track. If you suddenly get a bunch of strange square and cube roots all over the place, you might, for instance, have messed with the denominator a bit too much, so go back a step and try something else. |
heh, i allmost had it right
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Ah, Chruser, only if you done that 2 days earlier I would goten a 100% on my homework... :( stupid web assignments. Thanks anyway! Nice website you have there thanks for that too.
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whoa thanks.. ill be needing this next year and some of this year...
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Feel free to shout again if you need more help, and I just might be able to find out what I'm doing.
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Well that is true up until xy - 15y - 17 = x
From there you need to subtract x from both sides and add 15y and 17 to both sides. That gives you xy - x = 15y + 17 Then factor out the x which gives you x(y - 1) = 15y + 17 Then divide both sides by (y - 1) x = (15y + 17)/(y - 1) |
Why can't we just solve for X? It's a lot easier.
-14y-17=1 -14y=18 y=-1.29 xy-15y=x+17 -1.29x-(15 X -1.29)=x+17 X=1.03 Damn you smart people. |
I used MATHS and solved it easily.
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Well you can't solve for y because when you divided by x on both sides, you fucked up. You would have also had to divide 15y and 17 by x also.
To keep both sides of the equation equal, you have to divide both sides by the same thing. You can't divide different terms by something, it must be the whole. |
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