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-   -   A simple math problem (http://zelaron.com/forum/showthread.php?t=22907)

Ganga 2003-10-04 03:52 PM

A simple math problem
 
I got stuck on this part, some one help please.

I need to solve for X:


Y=(X+17)/(x-15)


The answer should be like X= Y+something/ Y+something.

Mantralord 2003-10-04 04:08 PM

I think its X=(x+17+15y)/y

Ganga 2003-10-04 04:25 PM

Thanks for trying, but you have to put all x on 1 side. The question was to find the inverse of that funtion.

kaos 2003-10-04 04:29 PM

Quote:

Originally Posted by Ganga
A simple math problem


Define SIMPLE!

platnum 2003-10-04 04:32 PM

x=y-17

Sovereign 2003-10-04 04:34 PM

Thats not simple math...thats retard math...

Ganga 2003-10-04 04:41 PM

Appearly you are worst than retard.

!King_Amazon! 2003-10-04 04:42 PM

I know it looks like a fucked up "S" on a graph.

Sovereign 2003-10-04 04:43 PM

Ummm no ganga. ITs because i dont feel like doing ur math homework for you you lazy bum.

Ganga 2003-10-04 04:48 PM

Appearly you don't even know how to read either. Reread my first post couple times, and if you still have problem understanding, you should really quite school.

and stop spamming.

!King_Amazon! 2003-10-04 04:49 PM

Quote:

Originally Posted by Ganga
you should really quite school.


Sovereign 2003-10-04 04:49 PM

i reread it once, and i still dont see what your talking about...the retard math problem statement was aimed towards platnum because of his x=y-17...thats for retards, because its already answered.

Ganga 2003-10-04 04:55 PM

x=y-17 is wrong, "its already answered"???

Sovereign 2003-10-04 04:57 PM

NO NO NO . it hought he was giving an exdample of a simple math problem. you said solve for x, i thought his problem was x=y-17. I called it a retard problem becuase that was already solved for x.

Ganga 2003-10-04 05:00 PM

LOl, Ok then I think i got everything wrong then, my bad calling you. We really need some system that say, this post is refer to post # 1 or what ever.

Sovereign 2003-10-04 05:02 PM

iz all good :)

!King_Amazon! 2003-10-04 05:07 PM

It seems to me that x is always = to 15, which isn't possible since you can't divide by 0. Let me try this again.

uncapped 2003-10-04 05:10 PM

Uh, y = 2x?

I dunno, I'm in stupid people math.

Ganga 2003-10-04 05:12 PM

The answer should be something like this:


f(x) = Ay + B/Cy + D


and I have to find the values for A, B, C, D with A > 0.

That's the question.

I know C is 1 that's all I know for now.

!King_Amazon! 2003-10-04 05:14 PM

Y | X
-5 | 9.66666....
-2 | 4.33333....
0 | -17
-2 | 47
-5 | 23


If you can figure out what the function is, I'm proud of you.

This is too hard for my sophomoreness.

Ganga 2003-10-04 05:21 PM

Did you just put that function on the calulator and look at the table?

!King_Amazon! 2003-10-04 06:06 PM

No, I graphed the function then graphed y=-5 y=-2 y=0 etc. and found the intersections.

Medieval Bob 2003-10-05 09:26 AM

I can give you:

x = 32/(y-1) + 15

platnum 2003-10-05 10:50 AM

http://www.iownjoo.com/freeimghost/platnum/mathzel.GIF

i came up with that, only way i could get x on one side.

Chruser 2003-10-05 12:23 PM

x = (15y + 17)/(y - 1)

Sovereign 2003-10-05 12:24 PM

Chruser anyway you can show your work in steps...im actually intrerested in how you did tha

Chruser 2003-10-05 12:51 PM

y = (x + 17) / (x - 15)
y(x-15) = x + 17
xy - 15y = x + 17
xy - x = 15y + 17
x(y - 1) = 15y + 17
x = (15y + 17) / (y -1)

Chruser 2003-10-05 01:01 PM

Oh, if you need to check your solution, you can always try this out:

http://www.hostsrv.com/webmab/app1/M...solve&s3=basic

Works really well up to exact fourth-grade solutions. If you want to see how good it really is, try solving this equation for x:

7a^4+17x^4+7x^3+17x^2+7x+7a^3=7

It might take a while, but the results are impressive.

Of course, if you have a lot of homework on a really tough equation to deal with, you can always use this web-based equation solver and check everything step-by-step to see if you're still on-track. If you suddenly get a bunch of strange square and cube roots all over the place, you might, for instance, have messed with the denominator a bit too much, so go back a step and try something else.

platnum 2003-10-05 01:06 PM

heh, i allmost had it right

Ganga 2003-10-05 05:47 PM

Ah, Chruser, only if you done that 2 days earlier I would goten a 100% on my homework... :( stupid web assignments. Thanks anyway! Nice website you have there thanks for that too.

slaynish 2003-10-05 05:51 PM

whoa thanks.. ill be needing this next year and some of this year...

Chruser 2003-10-06 09:58 AM

Feel free to shout again if you need more help, and I just might be able to find out what I'm doing.

!King_Amazon! 2003-12-06 09:32 AM

Quote:

Originally Posted by platnum
http://www.iownjoo.com/freeimghost/platnum/mathzel.GIF

i came up with that, only way i could get x on one side.

Well from that you can solve for Y, then solve for X, since X/X=1.

Medieval Bob 2003-12-06 10:03 PM

Well that is true up until xy - 15y - 17 = x

From there you need to subtract x from both sides and add 15y and 17 to both sides.

That gives you xy - x = 15y + 17
Then factor out the x which gives you x(y - 1) = 15y + 17
Then divide both sides by (y - 1)


x = (15y + 17)/(y - 1)

!King_Amazon! 2003-12-06 10:13 PM

Why can't we just solve for X? It's a lot easier.

-14y-17=1
-14y=18
y=-1.29

xy-15y=x+17
-1.29x-(15 X -1.29)=x+17
X=1.03

Damn you smart people.

RoboticSilence 2003-12-06 10:51 PM

I used MATHS and solved it easily.

Medieval Bob 2003-12-07 10:17 AM

Well you can't solve for y because when you divided by x on both sides, you fucked up. You would have also had to divide 15y and 17 by x also.

To keep both sides of the equation equal, you have to divide both sides by the same thing. You can't divide different terms by something, it must be the whole.


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