Zelaron Gaming Forum

Zelaron Gaming Forum (http://zelaron.com/forum/index.php)
-   The Lounge (http://zelaron.com/forum/forumdisplay.php?f=183)
-   -   A simple math problem (http://zelaron.com/forum/showthread.php?t=22907)

Ganga 2003-10-04 05:21 PM

Did you just put that function on the calulator and look at the table?

!King_Amazon! 2003-10-04 06:06 PM

No, I graphed the function then graphed y=-5 y=-2 y=0 etc. and found the intersections.

Medieval Bob 2003-10-05 09:26 AM

I can give you:

x = 32/(y-1) + 15

platnum 2003-10-05 10:50 AM

http://www.iownjoo.com/freeimghost/platnum/mathzel.GIF

i came up with that, only way i could get x on one side.

Chruser 2003-10-05 12:23 PM

x = (15y + 17)/(y - 1)

Sovereign 2003-10-05 12:24 PM

Chruser anyway you can show your work in steps...im actually intrerested in how you did tha

Chruser 2003-10-05 12:51 PM

y = (x + 17) / (x - 15)
y(x-15) = x + 17
xy - 15y = x + 17
xy - x = 15y + 17
x(y - 1) = 15y + 17
x = (15y + 17) / (y -1)

Chruser 2003-10-05 01:01 PM

Oh, if you need to check your solution, you can always try this out:

http://www.hostsrv.com/webmab/app1/M...solve&s3=basic

Works really well up to exact fourth-grade solutions. If you want to see how good it really is, try solving this equation for x:

7a^4+17x^4+7x^3+17x^2+7x+7a^3=7

It might take a while, but the results are impressive.

Of course, if you have a lot of homework on a really tough equation to deal with, you can always use this web-based equation solver and check everything step-by-step to see if you're still on-track. If you suddenly get a bunch of strange square and cube roots all over the place, you might, for instance, have messed with the denominator a bit too much, so go back a step and try something else.

platnum 2003-10-05 01:06 PM

heh, i allmost had it right

Ganga 2003-10-05 05:47 PM

Ah, Chruser, only if you done that 2 days earlier I would goten a 100% on my homework... :( stupid web assignments. Thanks anyway! Nice website you have there thanks for that too.

slaynish 2003-10-05 05:51 PM

whoa thanks.. ill be needing this next year and some of this year...

Chruser 2003-10-06 09:58 AM

Feel free to shout again if you need more help, and I just might be able to find out what I'm doing.

!King_Amazon! 2003-12-06 09:32 AM

Quote:

Originally Posted by platnum
http://www.iownjoo.com/freeimghost/platnum/mathzel.GIF

i came up with that, only way i could get x on one side.

Well from that you can solve for Y, then solve for X, since X/X=1.

Medieval Bob 2003-12-06 10:03 PM

Well that is true up until xy - 15y - 17 = x

From there you need to subtract x from both sides and add 15y and 17 to both sides.

That gives you xy - x = 15y + 17
Then factor out the x which gives you x(y - 1) = 15y + 17
Then divide both sides by (y - 1)


x = (15y + 17)/(y - 1)

!King_Amazon! 2003-12-06 10:13 PM

Why can't we just solve for X? It's a lot easier.

-14y-17=1
-14y=18
y=-1.29

xy-15y=x+17
-1.29x-(15 X -1.29)=x+17
X=1.03

Damn you smart people.

RoboticSilence 2003-12-06 10:51 PM

I used MATHS and solved it easily.

Medieval Bob 2003-12-07 10:17 AM

Well you can't solve for y because when you divided by x on both sides, you fucked up. You would have also had to divide 15y and 17 by x also.

To keep both sides of the equation equal, you have to divide both sides by the same thing. You can't divide different terms by something, it must be the whole.


All times are GMT -6. The time now is 04:53 AM.

Powered by vBulletin® Version 3.8.2
Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
This site is best seen with your eyes open.