| [18:03] System: Chruser
has joined the chat | | [18:03] Chruser:
The probability of what, exactly? A particular (first) outcome of, say, 4? | | [18:03] Chruser:
You could denote each sequence of rolls on the repeat-on-1 D6 as a string, say, "11114", implying the the first four rolls were 1, and the fifth was 4. So you're really asking for the probability of getting either of the strings 4, 14, 114, 1114, etc (out of the space of possible strings like 12, 6, 116, 11111113, etc). | | [18:04] Chruser:
The probability of getting a "first" roll of 4 is P("4" ∪ "14" ∪ "114" ∪ ...) = P("4") + P("14") + P("114") + ... = 1/6 + 1/6*1/6 + 1/6*1/6*1/6 + ... = 1/5. | | [18:16] Chruser:
Also, why the quotes? Five-sided dice are perfectly fine. :p | | [18:44] System: Chruser
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