C programming Count uppercase letters in a sentence

[deadlock75]

I don't know where to start or how to write the program I need some help I am trying to program an uppercase character is an character whose ASCII value is between 65(A) and 90(Z). I need to write a program that prompts the user to enter a string from the keyboard and will count the number uppercase character and replace each uppercase character by the corresponding lowercase character.

[Demosthenes]

I don't know where to start or how to write the program I need some help I am trying to program an uppercase character is an character whose ASCII value is between 65(A) and 90(Z). I need to write a program that prompts the user to enter a string from the keyboard and will count the number uppercase character and replace each uppercase character by the corresponding lowercase character.


#include <stdio.h>

int main(void)
{
char string[50];
gets(string);
int count = 0;
int i;
for(i = 0; string[i]; i++)
{
if(string[i] >= 'A' && string[i] <= 'Z')
{
count++;
}
}

printf("%d", count);
}

[WetWired]

Actually, it would be
for(i=0;i<strlen(string);i++)
not
for(i=0;i<string[i];i++)

[Demosthenes]

Actually, it would be
for(i=0;i<strlen(string);i++)
not
for(i=0;i<string[i];i++)

Actually, I don't even know why I did
i<string[i]

I meant to just say string[i]

I'll go ahead and change that.

But yea, WW's method is better. Use strlen.